Shafts · Static reactions and bending diagram

Shaft Bearing Reactions / Bending Moment Calculator

Mechanical Engineering Calculators for ideal shaft bearing reactions, shear-force magnitude, and maximum bending moment from two transverse point loads between supports.

Reference calculator #023

Enter bearing span and transverse point loads

Inputs stay in your browser. Values are normalized to canonical units before calculation.

Distance between the ideal left and right bearing reaction centers.

Positive transverse load magnitude in the single evaluated bending plane.

A positive load must act strictly between the two bearing centers.

Enter zero to model one point load; otherwise use a parallel downward load.

Measure from the left bearing center; the two load positions may be entered in either order.

Display bearing reactions, total load, and shear in this unit.

Display maximum and load-position moments in this unit.

Display maximum-moment locations and region length in this unit.

Calculated output

Results

shaft-bearing-reactions-bending-moment/1.0.0
Maximum bending moment between bearing centers700 N·m
Left bearing reaction R_A
2000 N
Right bearing reaction R_B
2000 N
Maximum internal shear-force magnitude
2000 N
Total downward transverse load
4000 N
Maximum-moment region start x
350 mm
Maximum-moment region end x
350 mm
Constant maximum-moment region length
0 mm
Bending moment at load 1 position
700 N·m
Bending moment at load 2 position
500 N·m

Valid simply supported shaft equilibrium result

Simply supported shaft reactions and bending momentTwo ideal bearing supports carry a shaft with two downward point loads. Reaction arrows and a piecewise-linear bending-moment diagram show the equilibrium result.P₁ = 2500 Nx₁ = 350 mmP₂ = 1500 Nx₂ = 750 mmR_A = 2000 NR_B = 2000 NL = 1000 mmBending-moment diagramM_max = 700 N·mMaximum from 350 mm to 350 mm · |V|_max = 2000 N
Ideal simply supported equilibrium for co-directional point loads between bearing centers. The shaded line is the positive bending-moment diagram, not a shaft-deflection curve.
Scope and assumptions
  • The shaft is modeled as a statically determinate simply supported beam between two ideal bearing centers; the supports transmit transverse force but no reaction moment.
  • Both entered loads are downward, parallel point-load magnitudes acting in one bending plane and strictly between the bearing centers when positive.
  • The shaft and bearing self-weight, distributed loads, applied couples, axial force, torque, overhung loads, and loads in a second bending plane are excluded.
  • Reactions and internal bending moments follow static equilibrium. Shaft stiffness, section geometry, material, deflection, bearing compliance, and load sharing do not affect this statically determinate result.
  • The reported maximum is the positive sagging bending-moment magnitude for this co-directional loading model; a zero-shear region may create a constant maximum-moment plateau.
  • Stress, fatigue, dynamics, critical speed, bearing selection, fits, tolerances, and final shaft approval are excluded.

Calculation engine: shaft-bearing-reactions-bending-moment/1.0.0

Static-equilibrium equations

Model the shaft centerline as a simply supported beam from the left bearing center A at x = 0 to the right bearing center B at x = L. Both point loads act downward in the same plane.

R_B = (P₁x₁ + P₂x₂) / L
R_A = P₁ + P₂ − R_B

At any position x between the supports, the calculator uses the loads to the left of the section:

V(x) = R_A − Σ(Pᵢ for xᵢ ≤ x)
M(x) = R_Ax − Σ[Pᵢ max(0, x − xᵢ)]
Symbol Meaning Canonical calculation unit
L Distance between bearing reaction centers mm
P₁, P₂ Downward transverse point-load magnitudes N
x₁, x₂ Load positions measured from the left bearing mm
R_A, R_B Upward ideal support-reaction magnitudes N
V(x) Internal shear force N
M(x) Internal bending moment N·m after conversion

Worked two-load example

Use the default inputs: L = 1,000 mm, P₁ = 2,500 N at x₁ = 350 mm, and P₂ = 1,500 N at x₂ = 750 mm.

  1. Moment equilibrium about A gives R_B = 2,000 N.
  2. Force equilibrium gives R_A = 2,000 N.
  3. At the first load, M(x₁) = 2,000 × 350 = 700,000 N·mm = 700 N·m.
  4. At the second load, M(x₂) = 2,000 × 750 − 2,500 × 400 = 500 N·m.
  5. The maximum bending moment is therefore 700 N·m at x = 350 mm, and the maximum internal shear-force magnitude is 2,000 N.

The reactions sum to the applied load, and the bending moment returns to zero at the right simple support. These checks verify internal equilibrium; they do not verify whether the entered loads represent the actual machine.

Why maximum moment can be a region

Between point loads, shear is constant and bending moment changes linearly. If shear is zero between two load positions, the bending moment remains constant across that interval. A symmetric pair of equal loads is a common example. The calculator therefore reports a maximum-moment region start, end, and length instead of always claiming one unique critical coordinate.

Establish the shaft free-body diagram first

Enter forces only after resolving the actual gear, belt, chain, coupling, rotor, or process loads into one bending plane. The load position is the force line of action measured from the left bearing reaction center, not necessarily a component face, shaft shoulder, housing edge, or bearing width edge.

Loads in perpendicular planes must be analyzed separately. If the applicable method permits, combine the resulting bending-moment components at a section as a vector magnitude before transferring the controlling moment to the Shaft Combined Bending and Torsion Calculator. Do not simply add perpendicular force magnitudes as though they act in the same plane.

Bearing reactions are not complete bearing selection loads

The calculated reactions are ideal single-plane transverse support forces. A real bearing arrangement can include radial loads in two planes, axial thrust, preload, moments, internal clearance, housing and shaft deflection, unequal load sharing, thermal effects, and arrangement-specific constraints. Use the bearing manufacturer’s method and verified arrangement geometry before passing a reaction into a bearing rating calculation.

Engineering scope and limitations

This calculator covers a statically determinate shaft between two ideal simple supports with up to two co-directional point loads acting strictly inside the bearing span. It excludes:

  • overhung loads, supports outside the entered span, more than two point loads, distributed loads, shaft or component self-weight, and applied couples;
  • opposite-direction loads, signed reactions, loads in multiple bending planes, axial forces, torque, gyroscopic loads, and transient or impact loading;
  • bearing width, contact-center migration, support stiffness, housing flexibility, preload, clearance, internal bearing load distribution, and misalignment;
  • shaft diameter, section changes, stress, stress concentration, deflection, slope, yielding, fatigue, critical speed, vibration, damping, and resonance;
  • gear, belt, chain, coupling, or process-force derivation; catalog bearing selection; static or dynamic bearing rating; lubrication; contamination; and life prediction;
  • tolerances, manufacturing feasibility, stock selection, inspection, safety factors, standards compliance, and engineering approval.

Use a complete machine free-body diagram, verified operating and design loads, the governing shaft and bearing design method, and qualified engineering review before releasing a drawing or selecting components.

Frequently asked questions

How are the two shaft bearing reactions calculated?

The right reaction follows moment equilibrium about the left bearing: R_B = (P₁x₁ + P₂x₂)/L. The left reaction then follows vertical force equilibrium: R_A = P₁ + P₂ − R_B.

Where does the maximum bending moment occur?

With only co-directional point loads between simple supports, bending moment is piecewise linear, so the maximum occurs at a load position or across a zero-shear plateau between load positions. The calculator reports both the start and end of the maximum region.

Can I use only one point load?

Yes. Set either load magnitude to zero. Keep its unused position between the bearing centers so the shared URL and diagram state remain valid.

Can this calculator handle an overhung gear or pulley?

No. Both positive loads must lie strictly between the two bearing centers. An overhung load requires a different free-body model and can create a different reaction and moment pattern.

Does the result give the bearing catalog load?

No. It reports ideal transverse support reactions in one plane. Bearing selection may require vector combination across planes, axial load, arrangement-specific load sharing, dynamic factors, static checks, speed, life, lubrication, and manufacturer data.

References and review status

Reviewed . References support simply supported beam equilibrium, point-load reactions, shear and bending-moment construction, and unit conversion. They do not establish the actual shaft load case, bearing load distribution, fatigue strength, or design approval.